<span>a rectangle rhombus(parallelogram) since even a parallelogram has diagonals</span>
Step-by-step explanation:
Perimeter of a rectangle = 2(L+W)
L is the length of the rectangle:
W is the width of the rectangle.
Given
Perimeter = 214feet
If the length is 41 ft longer than the width, then L = 41+W
Substitute L = 41+W into the formula:
P = 2(L+W)
214 = 2(41+W+W)
214 = 2(41+2W)
214 = 82+4W
4W = 214-82
4W = 132
W = 132/4
W = 33 feet
Since L = 41+W
L = 41+33
L = 74 feet
Hence the dimension of the field is 74ft by 33ft
<em>The width of the playing field is 33feet</em>
Step-by-step explanation:
given,radius =5 m
height =8 m
now, v=pi×r^2×h
=(3.14×5^2×8)m^3
=628m^3
therefore the volume is 628m^3 is the answer
1) x= -7
2) x= -5
3) x=-22
4) x =8
Not sure about the last one tho
I tried to help :)
Answer: false
Step-by-step explanation: dunno
