Answer:
Given: circle
diameter = 10 cm => radius (R) = 5 cm
Find: measure of angle bounding sector = 11 π sq. cm.
Plan: determine what part of the circle’s total area equals the sector’s area.
Total Area of Circle A = π R^2 = π 5^2 = 25 π sq. cm.
Therefore: Sector Area = 11 π cm^2/25 π cm^2 = 11/25
Since the sector is 11/25 th of the circles area, the sector angle will measure 11/25 th of the circle’s circumference. They are proportional.
C = 2 π R = 2 π (5) = 10 π cm
Sector Arc = measure of sector angle = 11/25 (10 π) =
22π/5 radians
Answer: Sector Arc = 22π/5 Radians
Answer:
cos(θ) = 3/5
Step-by-step explanation:
We can think of this situation as a triangle rectangle (you can see it in the image below).
Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.
Here we want to find cos(θ).
You should remember:
cos(θ) = (adjacent cathetus)/(hypotenuse)
We already know that the adjacent cathetus is equal to 3.
And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:
3^2 + 4^2 = H^2
We can solve this for H, to get:
H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5
The hypotenuse is 5 units long.
Then we have:
cos(θ) = (adjacent cathetus)/(hypotenuse)
cos(θ) = 3/5
Find the interquartile range of 17, 23, 8, 5, 9, 16, 22, 11, 13, 15, 17, 18
Yuri [45]
8.25
Hope I helped! ( Smiles )
Se calcula que la aceleración es - 8,35 m/s.
<h3 /><h3>¿Qué es la aceleración?</h3>
Ahora sabemos lo siguiente de la pregunta;
Velocidad inicial (u) = 60 km/h o 16,7 m/s
Tiempo empleado (t) = 2 s
Dado que;
v = tu + en
v = 0 m/s porque el carro se detenía
tu = -en
a = -(u/t)
a= -1(6,7 m/s/2 s)
a =- 8,35 m/s
La aceleración es negativa porque la velocidad disminuye con el tiempo.
Obtenga más información sobre la aceleración: brainly.com/question/12550364
#SPJ1
Answer:
Second option. "Sue wants to cover the lid of a box with paper. How much paper should she buy?"
Explanation:
The first option relies upon volume.
The last two options relies on side lengths.
The second option is relies on area because you have to calculate the area of the lid to know how much paper can be used to cover it.
