Find the area of the triangles and smal ler square and add them together ; and find the area of the complete square and set them equal to each other (these are known truths)
triangle: l×w /2
square: s^2
There are 4 triangles so
4 (1/2ab)+c^2= (a+b)(a+b)
simplify
2ab+c^2= a^2+2ab+b^2
-2ab both sides
c^2=a^2+b^2
tada!! it's proven :)
Answer:
Both A and B are possible.
Step-by-step explanation:
It's both!
This is a might tricky. First you have to find the altitude. You have to determine if this is a real triangle.
Sin(22) = opposite / hypotenuse. The hypotenuse = 111. The angle is 22
opposite = hypotenuse * sin(22)
opposite = 111 * sin(22)
opposite = 41.58 and this is the altitude.
What have you learned?
Since 42 is larger than 41.58 you have 2 solutions to the triangle. One of the angles is acute, and the other one is obtuse. They are supplementary angles.
Sin(C) / c = Sin(A) / a
Sin(C) = c * Sin(22) / 42
Sin(C) = 111*sin(22)/ 42
Sin(C) = .99003
Sin(C) = 81.9
So that's your first answer. The second answer comes from Finding the supplement to this angle
supplement + 81.9 = 180
supplement = 180 - 81.9
supplement = 98.1
Well first off you multiply the parenthesis 1/4(x-12) you get -1=1/4x-3 then you subtract the one so now the y can be by itself the you get Y=1/4x-2
Here's how to solve this equation:
4 - <span>√2x-5 = 1
</span><span>√2x-5 = 4-1
</span><span>√2x-5 = 3 (now we have to square both sides to get rid of the root)
</span><span>√2x-5=3 / ^2
</span>(<span>√2x-5)^2 = 3^2
2x-5 = 9
2x = 9+5
2x = 14
x = 14/2
x = 7
The correct answer is 7. </span>