Answer:
(x^2+y)x^3 y^5
Step-by-step explanation:
(x^2 + y)x^4 y^3 / x y^2
(x^2 + y)x^4 - 1 y^3 * y^2
(x^2 + 7)x^3 y^3 * y^2
(x^2 + y)x^3 y^3 +^2
(x^2 + y)x^3 y^5
Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
Answer: the probability is 0.25
Step-by-step explanation:
We have 10 numbers:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9
Of those, the odd ones are:
1, 3, 5, 7, 9
So we have 5 odd numbers.
The probability that the outcome is an odd number is equal to the number of odd numbers divided the total number of numbers:
p = 5/10 = 0.5
For the second spin the probability is the same, p = 5/10, because the first outcome does not affect the results of the second spin.
The probability of spining an odd number both times, then is the joint probability for two times this same event:
P = (5/10)(5/10) = 0.5*0.5 = 0.25
or 25% in percent form
Answer:
16 m
Step-by-step explanation:
I did not even understand that equation
