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ELEN [110]
3 years ago
11

A typical human stomach can hold up to 4 cups of food. Write an inequality to represent how many cups of food a stomach can hold

.
Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0
5cups \= 4 cups

5 represents the amount of food held in the stomach and 4 represents the amount of food that can be held in the stomach
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PLEASE HELP ITS DUE REALLY SOON!!!
oksian1 [2.3K]

Answer:

-(5x-21)/6 so d

Step-by-step explanation:

to do inverse functions you want to replace the x in the function with y so x=(21-6y)/5, then solve for y and you will get the answer I got and its d

8 0
3 years ago
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
3 years ago
Please answer this correctly
aleksklad [387]

Answer:

63.2 = y

Step-by-step explanation:

The perimeter is the sum of all the sides

P = 7.8+ y+37.6 + y

171.8 = 7.8+ y+37.6 + y

Combine like terms

171.8 = 45.4 + 2y

Subtract 45.4 from both sides

171.8-45.4 = 45.4 + 2y -45.4

126.4 = 2y

Divide each side by 2

126.4/2 = 2y/2

63.2 = y

6 0
3 years ago
The following relations are written as equations. Which one is NOT a.
julia-pushkina [17]

Answer:

x = 4

Step-by-step explanation:

doesn't pass the vertical line test

8 0
3 years ago
Read 2 more answers
Madi has $8.80 in pennies and nickels.
shepuryov [24]
Let p = number of pennies.
Let n = number of nickels.

We are given that n= 2p and the total value is $8.80.

We know that a penny = $0.01 and that a nickel = $0.05.

So $0.01p + $0.05n = $8.80.

Substitute 2p for n:
$0.01p + $0.05*2p = $8.80

$0.01p + $0.10p = $8.80

$0.11p = $8.80

p = 80
So n = 2p = 2*80 = 160

Thus there are 80 pennies ($0.8) and 160 nickels ($8.00). The value of all the coins is $8.80.
7 0
3 years ago
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