Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Answer:
$720
Step-by-step explanation:
Given :
Mean, m = 600
Standard deviation, s = 120
Z = (x - m) / s
P(Z > x) = 84%
P(Z > x) = 0.84
Zscore corresponding to P(Z > x) = 0.84 will be -0.994
Hence,
-0.994 = (x - 600) / 120
120 * -0.994 = x - 600
119.28 = x - 600
119.28 + 600 = x
719.28 = x
Hence,
X = $720
F(x)=5/x
g(x)=2(x^2)+5x
f(x) has a domain of all real numbers excluding zero
g(x) has a domain of all real numbers
fog(x)=5/(2(x^2)+5x)
fog(x)=5/(x(2x+5))
fog(x) has a domain that excludes both zero and -5/2
