___

Mathematics

1 answer:

Reil [10]3 years ago

6 0

///)(;-(()3)3)3$$/$1(-(-(-((1;1;/;;/ ye ya “3

You might be interested in

a pool in the shape of rectangle has a perimeter of 80 feet. The pool is 8 Feet less wide than its long. Find the length and wid

Aneli [31]

Hello!

To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w

To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.

2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24

Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.

Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.

As our final answer, the width of the pool is 16 feet, and the length is 24 feet.

Hope this helps!

5 0

3 years ago

How do you solve 8n²-4n=18?

Pie

Step1.8 x 8=64+64=128

4 0

4 years ago

Solve for 2x^2-4x+5=6

Softa [21]

To solve for a variable, you need to get it (x) by itself.

2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula

a = 2 , b = -4 , c = -1
x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in your values
x = $\frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-1)} }{2(2)}$ Simplify
x = $\frac{4 \pm \sqrt{16 + 8} }{4}$ Simplify
x = $\frac{4 \pm 2\sqrt{6} }{4}$ Simplify by removing a 2 from every term
x = $\frac{2 \pm \sqrt{6} }{2}$ Simplify by taking the fraction apart
x = $\frac{2}{2} \pm \frac{ \sqrt{6} }{2}$ Change $\frac{2}{2}$ to 1
x = 1 $\pm \frac{ \sqrt{6} }{2}$ Simplify $\frac{ \sqrt{6} }{2}$ to $\sqrt{ \frac{3}{2} }$
x = 1 $\pm \sqrt{ \frac{3}{2} }$