Your answer to the question:
-12 4/5
And then decimal form:
-12.8
Answer:
n = 6
Step-by-step explanation:
1/2n + 3 = 6
1/2n = 3
n = 6
Answer:
A) Distance time graph
B) d(t) = 25t
C) The expression shows the distance more clearly.
Step-by-step explanation:
A) A distance time graph as seen in the attachment provides a representation of the distance travelled.
We are told the car travels at a constant speed of 100 meters per 4 seconds. Which means that 100 m for each 4 hours. So, for 200m, it's 8 hours like seen in the graph and for 300m,it's 12 hours as seen in the graph.
B) And expression for the distance is;
d = vt
Where;
d is distance in metres
v is speed in m/s and t is time
We are told that the car travels at a constant speed of 100 meters per 4 seconds.
Thus, v = 100/4 = 25 m/s
Distance travelled over time is;
d(t) = 25t
C) Looking at both A and B above, it's obvious that the expression of the distance shows a more clearer way of getting the distance because once we know the time travelled, we will just plug it into the equation and get the distance. Whereas, for the representation form, one will need to longer graphs if the time spent is very long.
Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
Answer:
- (3, 5), (1, 2) and (5, 1)
Step-by-step explanation:
Make three systems with pairs of lines and solve them to work out the vertices.
1) <u>Line 1 and line 2</u>
<u>Double the second equation and subtract equations:</u>
- -3x + 2y - 2(2x + y) = 1 - 2(11)
- -3x - 4x = 1 - 22
- -7x = - 21
- x = 3
<u>Find y:</u>
- 2*3 + y = 11
- 6 + y = 11
- y = 11 - 6
- y = 5
The point is (3, 5)
2) <u>Line 1 and line 3</u>
<u>Triple the second equation and add up equations:</u>
- -3x + 2y + 3(x + 4y) = 1 + 3(9)
- 2y + 12y = 1 + 27
- 14y = 28
- y = 2
<u>Find x:</u>
- x + 4*2 = 9
- x + 8 = 9
- x = 1
The point is (1, 2)
3) <u>Line 2 and line 3</u>
<u>Double the second equation and subtract the equations:</u>
- 2x + y - 2(x + 4y) = 11 - 2(9)
- y - 8y = 11 - 18
- - 7y = - 7
- y = 1
<u>Find x:</u>
- x + 4*1 = 9
- x + 4 = 9
- x = 5
The point is (5, 1)
