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viva [34]
3 years ago
7

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.
Mathematics
1 answer:
Alenkinab [10]3 years ago
6 0

Total distance = 380 miles

Let the time & distance of 1st day be = t1 & d1 respectively

Distance = Speed x Time

For second day : d2 = s2 x t2 ; d2 = 60 x t2

For first day : d1 = s1 x t1 ; d1 = 40 x t1

Given : d1 = d2 + 20 & t1 = t2 + 2 , putting these values in d1

d2 + 20 = 40 (t2 + 2)

Putting value of d2 ,

60 t2 + 20 = 40 t2 + 80

60 t2 - 40 t2 = 80 - 20

20t2 = 60

t2 = 60 / 20 ; t2 = 3

So, t1 = 3+2 = 5

Hence : d1 = 40 x 5 = 200 ; d2 = 60 x 3 = 180

Therefore , Total Distance = 200 + 180 = 380

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Equation 2: 2x+4y=16

We can either use the 'elimination' method or the 'substitution' method to solve this simultaneous equation.

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To make the two constants the same, think of common multiple. The lowest common multiple for 5 and 2 is 10

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Once the constant of 'x' is the same, then we can start the elimination process. Since our aim is to eliminate, one of the 'x' need to be in negative form. We can either multiply Equation 1 or Equation 2 by (-1)

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