Question

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.

Answer 1

Total distance = 380 miles

Let the time & distance of 1st day be = t1 & d1 respectively

Distance = Speed x Time

For second day : d2 = s2 x t2 ; d2 = 60 x t2

For first day : d1 = s1 x t1 ; d1 = 40 x t1

Given : d1 = d2 + 20 & t1 = t2 + 2 , putting these values in d1

d2 + 20 = 40 (t2 + 2)

Putting value of d2 ,

60 t2 + 20 = 40 t2 + 80

60 t2 - 40 t2 = 80 - 20

20t2 = 60

t2 = 60 / 20 ; t2 = 3

So, t1 = 3+2 = 5

Hence : d1 = 40 x 5 = 200 ; d2 = 60 x 3 = 180

Therefore , Total Distance = 200 + 180 = 380