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3 years ago

An integer is between -4 and -19. It is twice as far from -4 as it is from -19. What is the integer? SHOW ALL YOUR STEPS**

Mathematics

2 answers:

LuckyWell [14K]3 years ago

8 0

Answer:

this integer is -14

Step-by-step explanation:

19-4=15

the distance between -4 and the integer is 2x, the distance between the integer and -19 is x

x+2x=15

3x=15

x=5

-19+x=-19+5=-14

ohaa [14]3 years ago

5 0

Answer:

-12

Step-by-step explanation:

use a number line go back 8 spaces from 19 and back from negative 4

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3 years ago

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If line segment BH = 3, line segment BF = 10, line segment GH= 2, find HD 15 11 10.5 ?

pav-90 [236]

HD = 10.5

Step-by-step explanation:

Given BH = 3, GH = 2, BF = 10

Step 1: To find HF:

HF = BF – BH

HF = 10 – 3

HF = 7

Step 2: To find HD:

We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.

⇒ GH × HD = BH × HF

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3 years ago

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Let A be a 4 x 5 matrix and Let B be a 4 x 4 matrix. Suppose you were asked to multiply matrix A times matrix B. When multiplied

VMariaS [17]

Answer:

b. false

Step-by-step explanation:

when multiplying matrixes the number of columns of the first matrix must be equal as the number of rows of the second matrix, and since here matrix A has 4 columns but matrix B has 5 rows they can't be multiplied

8 0

3 years ago

T F IfA and B are similar matrices, then AT=BT

muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices $A$ and $B$ exists an invertible matrix $P$ for which

$[tex]B = P^{-1} AP$ [/tex]

∴ $B^{T} = (P^{-1})^{T} A^{T} P^{T} \\$

Also $P^{-1}P = I\\$

and $(P^{-1})^{T} = (P^{T})^{-1}$

∴ $(P^{-1})^{T}P^{T} = I$

so, $B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}$

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3 years ago

The product of three integers x, x+2, and x-5 is 240. What are the integers?

Dafna11 [192]

Answer:

8, 10, 3

Step-by-step explanation:

For finding real solutions to cubic equations and those of higher degree, I find a graphing calculator to be useful. The problem can be cast in the form ...

f(x) = 0

where f(x) is the difference between the product of the integers and 240:

f(x) = x(x +2)(x -5) -240

Then all we need to do is ask the calculator to show the x-intercept. It is x=8.

So, the three integers are ...

x = 8
x+2 = 10
x -5 = 3

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3 years ago