Answer: 1. F
2. C
3.a
4. E
5. D
6. B
Step-by-step explanation:
F(10)=300+35(10)
f(10)=300+350
650(10)=300+350
6500
M 1 = V 1 * d
m 2 = V 2 * d
Both tetrahedrons have the same density.
V = 1/3 * a²√3/4 * h
V 1 = 1/3 * 1² * √3 / 4 * √2 / √3 = √2 / 12 cm³
V 2 = 1/3 * 3²√3 /4 * √6 = 9√2 / 4 cm³
m 1 : m 2 = √2 /12 : 9√2/4
m 1 * 9√2 / 4 = m 2 * √2 / 12
m 1 = m 2 / 27
m 1 + m 2 = 100 g
m 2 / 27 + m 2 = 100 g / * 27
m 2 + 27 m 2 = 2700
28 m 2 = 2700
m 2 = 2700 : 28
m 2 = 96.42 g
Answer:
The weight of the bigger tetrahedron is 96.42 g.
All the angles must add to 180degrees in a triangle.
180 = 59 + 35 + x
180 = 94 + x
86 = x
Supplementary angles x and z add to 180
180 = x + z
180 = 86 + z
94 = z
Now the last triangle is with angles 11, z, and y
they must add to 180 so...
180 = 11 + z + y
180 = 11 + 94 + y
180 = 105 + y
75 = y
The answer is B.)
<span>Hope this helps!</span>
x = 73.21
Step-by-step explanation:
Consider triangle ABC. Since angle A is 45° and side BC is 100, then side AB is also 100.
Now consider triangle ABD. With angle A equal to 60°, we can use the definition of tangent to find the value of x:
tan 60 = BD/AB
sqrt(3) = (x + 100)/100
or
x + 100 = 100sqrt(3)
x = 100[sqrt(3) - 1]
= 73.21
