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Naddik [55]
4 years ago
7

Y+4x=10x-6 solve for x

Mathematics
2 answers:
7nadin3 [17]4 years ago
8 0

Answer:

(y-6)/6 = x

Step-by-step explanation:

y+4x=10x-6

Subtract 4x from each side

y+4x-4x=10x-4x-6

y = 6x-6

Add 6 to each side

y +6 = 6x-6+6

y+6 = 6x

Divide by 6

(y-6)/6 = 6x/6

(y-6)/6 = x



zzz [600]4 years ago
5 0

Answer:

x=\frac{6+y}{6}

Step-by-step explanation:

Given equation,

y+4x=10x-6----(1)

For solving this equation for x,

We need to isolate x in the left side of the equation,

Subtract 10x on the both sides of equation (1),

y+4x - 10x = -6

Subtract y on both sides,

-6x = -6 - y

Divide both sides by -6,

x=\frac{6+y}{6}

Which is the required equation.

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3 years ago
5pn-8p=7n-7. Solve for n.
Firlakuza [10]

Answer:

       -8p + 7

n = --------------

        8 - 5p

Step-by-step explanation:

Let's group the n terms in  5pn-8p=7n-7  .

Subtract 5pn from both sides.  This results in -8p = 7n - 7 - 5pn

Now add 7 to both sides.  This will group the n terms on the right side:

-8p + 7 = 7n - 5pn

Factor n out of 7n - 5pn:

-8p + 7 = n(7 - 5p)

Finally, divide both sides by (7 - 5n) to isolate n:

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n = --------------

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8 0
3 years ago
PLEASE I NEED THIS TODAY!!!
Troyanec [42]

Answer:

Option D y\leq -3x-3 and y

Step-by-step explanation:

step 1

<u>Find the equation of the inequality A</u>

we know that

The solution of the inequality A (dashed line)  is the shaded area below the dashed line

The equation of the dashed line is y=-\frac{1}{2}x+2

therefore

The equation of the inequality A is y

step 2

<u>Find the equation of the inequality B</u>

we know that

The solution of the inequality B (solid line)  is the shaded area below the solid line

The equation of the solid line is y=-3x-3

therefore

The equation of the inequality B is y\leq -3x-3

The system of linear inequalities is

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6 0
4 years ago
The third through the fifth terms of a geometric sequence are given by a3 = 18, a4 = 27 , and a5 = 81/2
Kaylis [27]

Let <em>a</em> be the first term in the sequence. If <em>r</em> is the ratio between consecutive terms, then the second term is <em>ar</em>, the third term is <em>ar </em>^2, the fourth is <em>ar</em> ^3, and so on, up to the <em>n</em>-th term <em>ar</em> ^(<em>n</em> - 1).

So the third, fourth, and fifth terms are such that

<em>ar</em> ^2 = 18

<em>ar</em> ^3 = 27

<em>ar</em> ^4 = 81/2

Solve for <em>a</em> and <em>r</em> :

(<em>ar</em> ^3) / (<em>ar</em> ^2) = 27/18   =>   <em>r</em> = 3/2

<em>ar</em> ^2 = <em>a</em> (3/2)^2 = 9/4 <em>a</em> = 18   =>   <em>a</em> = 8

Then the <em>n</em>-th term in the sequence is

<em>ar</em> ^(<em>n</em> - 1) = 9 (3/2)^(<em>n</em> - 1)

You can rewrite this by first rewriting 9 = 3^2, then

9 (3/2)^(<em>n</em> - 1) = 3^2 * 3^(<em>n</em> - 1) / 2^(<em>n</em> - 1) = 3^(<em>n</em> + 1)/2^(<em>n</em> - 1)

6 0
3 years ago
Mr. Ledger buys a box of 24 donuts for a lesson in his math class about circumference.
MA_775_DIABLO [31]

Answer:

donuts L that are left at the end of the day when U donuts are being used during the day: y=24-x. You minus x, the # of donuts being used from 24, the total amount of donuts. To get your y.

Step-by-step explanation:

4 0
2 years ago
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