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Molodets [167]
3 years ago
7

I need help, I don’t get this

Mathematics
1 answer:
Dovator [93]3 years ago
8 0

Answer:

2a. One Solution

2b. Infinite Solutions

2c. No Solution

Step-by-step explanation:

In all the problems club terms with x on one side and the constants on the other side.

2a. 6x + 4x - 6 = 24 + 9x

⇒ 10x - 6 = 24 + 9x

Subtracting 9x and adding 6 on both sides;

⇒ 10x - 9x = 24 + 6

⇒ x = 30

The only possible value of x that could satisfy the equation is 30. So, there is only one possible solution to the equation.

2b. 25 - 4x = 15 - 3x + 10 - x

Clubbing like terms;

25 - 15 - 10 = 4x - 3x - x

⇒ 25 - 25 = 4x - 4x

⇒ 0 = 0

Note that any value of 'x' could satisfy this equation. So, there are infinite solutions to the equation.

2c. 4x + 8 = 2x + 7 + 2x - 20

⇒ 4x - 2x - 2x = - 20 + 7 + 8

⇒ 4x - 4x = -5

⇒ 0 = -5

This is absurd. No value of 'x'  can satisfy this. So, there are no solutions to this equation.

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