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3 years ago

7

The equation below has one solution 9X -10 equals 3X +2 what is the solution to the equation

1 answer:

djyliett [7]3 years ago

5 0

Answer:

X= 2

Step-by-step explanation:

9x-10

(9*2)-10

18-10

8

3x+2

(3*2)+2

6+2

8

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8(3a+5)???? please help!!!!!! ASAP!!!!

r-ruslan [8.4K]

I'm assuming your teacher wants you to distribute. If so, then you multiply the outer term 8 by each term inside (3a and 5). After that you add.

8 times 3a = 24a

8 times 5 = 40

So 8(3a+5) becomes 24a+40

We do not combine 24a and 40 as they are not like terms. So we leave 24a+40 as it is.

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iris [78.8K]

Answer:

About 9.38

Step-by-step explanation:

Since the $\sqrt{88}$ is between the $\sqrt{81}$ and the $\sqrt{100}$ which simplified is 9 and 10, you just need to guess and check. Eventually you'll get about 9.38 (I used Google cause I was lazy) And if it isn't between the numbers 9 & 10, it's wrong.

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earnstyle [38]

I believe the answer is true.

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3 years ago

find the standard form of equation of a line perpendicular to 4X plus 5Y equals 40 that includes the point -10, -3

snow_tiger [21]

The equation of line in standard form is 5x - 4y = -38

<em><u>Solution:</u></em>

Given that we have to find the equation of line perpendicular to 4x + 5y = 40 that includes the point (-10, -3)

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

4x + 5y = 40

Rearranging to slope intercept form, we get

5y = -4x + 40

$y = \frac{-4}{5}x + \frac{40}{5}\\\\y = \frac{-4}{5}x + 8$

On comparing the above equation with eqn 1,

$m = \frac{-4}{5}$

We know that product of slope of line and slope of line perpendicular to given line is equal to -1

Therefore,

$\frac{-4}{5} \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{5}{4}$

Now find the equation of line with slope 5/4 and passing through (-10, -3)

Substitute $m = \frac{5}{4}$ and (x, y) = (-10, -3) in eqn 1

$-3 = \frac{5}{4}(-10) + c\\\\-3 = \frac{-25}{2} + c\\\\c = -3 + \frac{25}{2}\\\\c = \frac{-6 + 25}{2}\\\\c = \frac{19}{2}$

Substitute $c = \frac{19}{2}$ and $m = \frac{5}{4}$ in eqn 1

$y = \frac{5}{4}x + \frac{19}{2}$

The standard form of an equation is Ax + By = C

Therefore,

$\frac{5}{4}x - y = -\frac{19}{2}\\\\\frac{5x - 4y}{4} = \frac{-19}{2}\\\\5x - 4y = -38$

Thus the equation of line in standard form is found

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