A manager wants to test whether two normally distributed and independent populations have equal variances. the appropriate test statistic for this test is a "F-statistics."
<h3>
What is F-statistics?</h3>
An F statistic is a value obtained after performing an ANOVA test or even a regression analysis to determine whether the means of two populations differ significantly.
Some key features regarding the F-statistics are-
- It is comparable to a T statistic from the a T-Test; a T-test would then inform you when a single result is statistically significant, whereas a F test would then tell you if a set of variables is statistically significant.
- When determining whether your total results are significant, you must use the F statistic in conjunction with the p value. Why?
- A significant result does not imply that all of your variables have been significant.
- The statistic is simply comparing the cumulative influence of all the variables.
To know more about the F-statistics, here
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Answer:the first one opn and qps
Step-by-step explanation:
The formula for perimeter is:
<span>P = 2 h + 2 w</span>
where P is perimeter = 120 cm, h is height, w is width
we are also given that: h = (2/3) w, therefore:
P = 2 (2/3) w + 2 w = 120
(4/3) w + 2 w = 120
w = 36 cm
Therefore l is:
l = (2/3) w = 24 cm
<span>Hence the dimension should be 24cm by 36 cm</span>
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.
Explanation:
A) The probability that it is brown is the percentage of brown we have. Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%. The probability that one drawn is yellow or blue would be the two percentages added together: 15+20 = 35%. The probability that it is not green would be the percentage of green subtracted from 100: 100-5=95%. Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events. All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.
The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:
0.85^3 = 0.614 = 61.4%.
The probability that at least one is green is computed by subtracting 1-(probability of no green). We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
