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2 years ago

Explain how the GCF is used to factor an expression?

1 answer:

6 0

When factoring, it's easier to "pick out" the GCF first because it makes it simpler to factor even further. Otherwise, you will be troubled with lots of numbers and variables, so it will just get confusing.

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3q+4+9=-14 <br> what is Q

BlackZzzverrR [31]

Hi! Your answer is q = -9

Please see an explanation for a better and clear understanding to your problem.

Any questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

Since we want to solve for q-term. That means we are going to isolate q-term.

$\huge{3q+4+9=-14}$

We can add 4 and 9 together.

$\huge{3q+13=-14}$

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

$\huge{3q+13-13=-14-13}\\\huge{3q=-27}$

We are reaching to the final step where we divide the whole equation by 3.

$\huge{\frac{3q}{3}=-\frac{27}{3}}\\\huge{q=-9}$

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!

To check the answer, simply substitute q = -9 in the equation.

$\huge{3q+4+9=-14}\\\huge{3(-9)+13=-14}\\\huge{-27+13=-14}\\\huge{-14=-14}$

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.

Hope this helps!

5 0

2 years ago

Da<br> A<br> Solve the equation 2x^2+3=0

Anika [276]

Answer:

x = ±i(√6 / 2)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Algebra I</u>

Solving quadratics

<u>Algebra II</u>

Imaginary root i

√-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

2x² + 3 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

[Subtraction Property of Equality] Subtract 3 on both sides: 2x² = -3
[Division Property of Equality] Divide 2 on both sides: x² = -3/2
[Equality Property] Square root both sides: x = ±√(-3/2)
Simplify: x = ±i(√6 / 2)

4 0

3 years ago

Unit activity: exponential and logarithmic functions

nirvana33 [79]

We will conclude that:

The domain of the exponential function is equal to the range of the logarithmic function.
The domain of the logarithmic function is equal to the range of the exponential function.

<h3>Comparing the domains and ranges.</h3>

Let's study the two functions.

The exponential function is given by:

f(x) = A*e^x

You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:

y > 0.

For the logarithmic function we have:

g(x) = A*ln(x).

As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

$\lim_{x \to \infty} ln(x) = \infty \\\\ \lim_{x \to0} ln(x) = -\infty$

So the range of the logarithmic function is the set of all real numbers.

<h3>So what we can conclude?</h3>

The domain of the exponential function is equal to the range of the logarithmic function.
The domain of the logarithmic function is equal to the range of the exponential function.

If you want to learn more about domains and ranges, you can read:

brainly.com/question/10197594

3 0

1 year ago

Apex learning 6.8.5 question 3 answer

Maurinko [17]

Answer:

i need more info

Step-by-step explanation:

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3 years ago

Todd has $124 in his checking account. He wrote two checks for $13.96 and $21.67 and transferred $14 into his checking from

dangina [55]

Answer: $74.37

Step-by-step explanation:

7 0

2 years ago