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kramer
3 years ago
8

Explain how the GCF is used to factor an expression?

Mathematics
1 answer:
scoundrel [369]3 years ago
6 0

When factoring, it's easier to "pick out" the GCF first because it makes it simpler to factor even further. Otherwise, you will be troubled with lots of numbers and variables, so it will just get confusing.

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Multiply or divide as indicated. <br><br> x 2 • x 5
WARRIOR [948]
Hi there!

{x}^{2}  \times  {x}^{5}  = x {}^{2 + 5}  =  {x}^{7}

We can also write is out entirely.
{x}^{2}  = x \times x
{x}^{5}  = x \times x \times x \times x \times x
{x}^{2}  \times  {x}^{5}  = \\  (x \times x ) \times (x \times x \times x \times x \times x) =  \\ x \times x \times x \times x \times x \times x \times x =  \\  {x}^{7}
6 0
3 years ago
need answers to this asap. I am a multiple of 70. I'm between 300 and 500. I'm 20 more than a 100. who am I
Jlenok [28]
Im not 100% sure but I would say 420
5 0
3 years ago
Read 2 more answers
Please help i don't know what I'm doing ​
gulaghasi [49]

Answer:

11 is the answer

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The ratio of the profit, material cost and production labour of an article is 5:7:13.
IRINA_888 [86]

Answer:

The cost of producing the article is -3500 (Negative cost)

Step-by-step explanation:

The given parameters are

The ratio of the profit to material cost to production labor = 5:7:13

The amount of the material cost = 840 + Labor cost

Let the total cost = X

Therefore, we have;

The fraction of the total cost that is material cost = 7/(5 + 7 + 13) = 7/25

Therefore, the material cost = 7/25 × X

The fraction of the total cost that is labor cost = 13/(5 + 7 + 13) = 13/25

Therefore, the labor cost = 13/25 × X

However, the amount of the material cost = 840 + Labor cost, which gives;

7/25 × X = 13/25 × X + 840

7/25 × X - 13/25 × X = 840

-6/25 × X= 840

X = 840/(-6/25) = 840×(-25/6) = -3500

The cost of producing the article = -3500.

8 0
3 years ago
Find the equation of the line tangent to the function at the given point f(x)=5x^2 at x=10
Svet_ta [14]

f(x) = 5x²

f(10) = 5(10)²  = 5(100)  = 500

f'(x) = 10x

f'(10) = 10(10)   = 100  

Now, find the line that passes through (10, 500) and has a slope of 100

y - y₁ = m(x - x₁)

y - 500 = 100(x - 10)

y - 500 = 100x - 1000

        y = 100x - 500

8 0
3 years ago
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