Answer:
The solutions are x = 1.24 and x = -3.24
Step-by-step explanation:
Hi there!
First, let´s write the equation:
log[(x² + 2x -3)⁴] = 0
Apply the logarithm property: log(xᵃ) = a log(x)
4 log[(x² + 2x -3)⁴] = 0
Divide by 4 both sides
log(x² + 2x -3) = 0
if log(x² + 2x -3) = 0, then x² + 2x -3 = 1 because only log 1 = 0
x² + 2x -3 = 1
Subtract 1 at both sides of the equation
x² + 2x -4 = 0
Using the quadratic formula let´s solve this quadratic equation:
a = 1
b = 2
c = -4
x = [-b± √(b² - 4ac)]/2a
x = [-2 + √(4 - 4(-4)·1)]/2 = 1.24
and
x = [-2 - √(4 - 4(-4)·1)]/2 = -3.24
The solutions are x = 1.24 and x = -3.24
Have a nice day!
1.) x = -3...this is a vertical line with an undefined slope. A parallel line to a vertical line is also a vertical line. A vertical line is represented by x = a number....that number being the x coordinate of ur point(4,2).
so ur parallel line is : x = 4 <==
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2.) y = -3/2x + 6....slope here is -3/2. A parallel line will have the same slope.
y = mx + b
slope(m) = -3/2
(2,-1)...x = 2 and y = -1
now we sub into the formula and find b, the y int
-1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
so ur parallel line is : y = -3/2x + 2 <==
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y = -x - 2....the slope here is -1. A parallel line will have the same slope
y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub into the formula and find b, the y int
-2 = -1(2) + b
-2 = -2 + b
-2 + 2 = b
0 = b
so ur parallel equation is : y = -x + 0 which can be written as : y = -x <=
Since only the first term has ax for coefficients the GCF cant be -3ax^5.
The GCF would be -3a
Factor -3a out of all the terms:
-3a(2x^7)-3a(-4a^5)-3a(a^4)
Now factor -3a out of the equation for the final answer:
-3a(2x^7-4a^5+a^4)
Construct<span> a perpendicular from the </span>incenter<span> to one side of the triangle to locate the exact radius. 3. place compass point at the </span>incenter<span> and measure from the center to the point where the perpendicular crosses the side of the triangle</span>
Answer:
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