Step-by-step explanation:
![ratio \:of \:surface \:areas\\=\frac{2[5\times 7 + 7\times 3+3\times 5]}{2[20\times 28+ 28\times 12+12\times 20] }\\\\=\frac{[35 + 21+15]}{[560+ 336+240] }\\\\=\frac{71}{1136}\\\\=\frac{1}{16}\\\\= 1\: :\: 16](https://tex.z-dn.net/?f=%20ratio%20%5C%3Aof%20%5C%3Asurface%20%5C%3Aareas%5C%5C%3C%2Fp%3E%3Cp%3E%3D%5Cfrac%7B2%5B5%5Ctimes%207%20%2B%207%5Ctimes%203%2B3%5Ctimes%205%5D%7D%7B2%5B20%5Ctimes%2028%2B%2028%5Ctimes%2012%2B12%5Ctimes%2020%5D%20%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3D%5Cfrac%7B%5B35%20%2B%2021%2B15%5D%7D%7B%5B560%2B%20336%2B240%5D%20%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3D%5Cfrac%7B71%7D%7B1136%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3D%5Cfrac%7B1%7D%7B16%7D%5C%5C%5C%5C%3C%2Fp%3E%3Cp%3E%3D%201%5C%3A%20%3A%5C%3A%2016)
Answer:
False
Step-by-step explanation:
I believe it's false because both triangle have the exact same measurements, they would have to be congruent
Answer:
28m⁷n⁵
Step-by-step explanation:
You would first multiply 14 by 2. You would then multiply (which is really addition when it comes to exponents) your like-term exponents.
(14m²n⁵)(2m⁵) =28m⁷n⁵
14(2) = 28
m² + m⁵=m⁷
n⁵ + 0 = n⁵
Set equations for both containers:
Condition one: $y=2x$
Condition two: $(y-3)=4.5(x-2)$
plug in $y$ from condition one into the second equation:
$2x-3=4.5x-9$
simplify gives: $2.5x=6$
$\boxed{x=2.4}$
$\boxed{y=4.8}$
