2 years ago

What methods could be used to solve the following quadratic equation x^2 +12-28=0

Mathematics

1 answer:

kakasveta [241]2 years ago

7 0

Answer:

Step-by-step explanation:

x^2 +12x-28=0

x^2+(14-2)x-28=0

x^2+14x-2x-28=0

X(X+14)-2(X+14)=0

(X+14)(X-2) is the factor of this quadratic equation.

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What methods could be used to solve the following ￼quadratic equation x^2 +12-28=0

What methods could be used to solve the following quadratic equation x^2 +12-28=0