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UkoKoshka [18]
3 years ago
8

What methods could be used to solve the following quadratic equation x^2 +12-28=0

Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Answer:

Step-by-step explanation:

x^2 +12x-28=0

x^2+(14-2)x-28=0

x^2+14x-2x-28=0

X(X+14)-2(X+14)=0

(X+14)(X-2) is the factor of this quadratic equation.

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Solve for w.<br> - 2w – 14= 2(w+1)<br> Simplify your answer as much
snow_tiger [21]

Answer:

w = -4

Step-by-step explanation:

<u>Step 1:  Distribute</u>

-2w - 14 = 2(w + 1)

-2w - 14 = 2w + 2

<u>Step 2:  Add 2w to both sides</u>

-2w - 14 + 2w = 2w + 2 + 2w

-14 = 4w + 2

<u>Step 3:  Subtract 2 from both sides</u>

-14 - 2 = 4w + 2 - 2

-16 = 4w

<u>Step 4:  Divide both sides by 4</u>

-16 / 4 = 4w / 4

<em>-4 = w</em>

<em />

Answer:  w = -4

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4 years ago
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the perimeter of a rectangle is at most 66 inches. the length is 2x + 6 inches and the width is x - 3 inches. write and solve an
Cloud [144]

Answer:

Step-by-step explanation:

<em>2( 2x + 6 ) + 2( x - 3 ) ≤ 66</em>

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3 years ago
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What is the value of the expression below when y=2 and z=8<br> 8y-z
MrRissso [65]

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Help with this please lol
NeTakaya

Answer:

x = 107

Step-by-step explanation:

44+29+107=180

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