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Firlakuza [10]
3 years ago
7

In rhombus LMNO, diagonals top enclose L N end enclose and top enclose M O end enclose intersect at P. If the measure of angle L

P M is represented by 2x + 70. Solve for x.
Mathematics
1 answer:
stich3 [128]3 years ago
5 0

9514 1404 393

Answer:

  x = 10

Step-by-step explanation:

The diagonals of a rhombus cross at right angles.

  2x +70 = 90

  2x = 20 . . . . . . . subtract 70

  x = 10 . . . . . . . . . divide by 2

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Step-by-step explanation:

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<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

<em>brainliest</em><em> </em><em>appreciated</em>

<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>

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3 years ago
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