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zaharov [31]
3 years ago
10

the table shows the number of students in 4 classes. the teachers are combining the classes and dividing the students in half to

form two groups for a project. write an expression to represent this situation. how many students are in each group

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0
(24+32+30+28) ÷ 2

Solving:
114 ÷ 2
57 students in each group
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The sum of two numbers is 16. One number is 3 times the other. Find the numbers.
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Answer:

X = 12

Y = 4

Step-by-step explanation:

X + Y = 16

X = 3Y

3Y + Y = 16

4Y = 16

Y = 4

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X = 12

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Which expression is NOT equivalent to 24 + 18?
Alex
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You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

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8 0
3 years ago
Please solve the following quadratic equation and show your work: x^2 -x =30
saveliy_v [14]
Rewriting the equation as a quadratic equation equal to zero:
     x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
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Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
     x + 5 = 0  => x = -5
     x - 6 = 0  => x = 6
Therefore, our solutions are x = -5 and x = 6.
8 0
3 years ago
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