Question

Match its group with its percentage or mean Using

Answer 1

(1)

Mean length of all fish in the sample - $\boxed{\sf{\red{6.2}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

= 6.2

(2)

Mean length of adult fish in the sample - $\boxed{\sf{\red{8.75}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

= 8.75

(3)

Mean length of juvenile fish in the sample - $\boxed{\sf{\red{4.5}}}$

Mean = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

= 4.5

(4)

Percentage of sample that were adult fish - $\boxed{\sf{\red{40}}}$

Percentage = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

% = 40

(5)

Percentage of sample that were juvenile fish - $\boxed{\sf{\red{60}}}$

Percentage = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

% = 60

(6)

Percentage of sample that were juveniles over 8 inches long - $\boxed{\sf{\red{10}}}$

Percentage = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

% = 10