Answer:
Step-by-step explanation:
p = .3
n = 150
p(bar ) = 1 - p = .7
=.037
b )
P ( .2 <p<.4 ) = P [ (.2 - .3) / .037 < z < ( .4 - .3 ) / .037 ]
= P [ (-2.7 < z < +2.7 ]
= .9965-.0035
= .993
c )
P ( .25 <p<.35 ) = P [ (.25 - .3) / .037 < z < ( .35 - .3 ) / .037 ]
= P [ (-1.35 < z < +1.35 ]
= .9115 - .0885
= .823
Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Answer:
<h2>49.49%</h2>
Step-by-step explanation:
volume of liquid in the flask= 200 cm^3
radius of the flask = 3 cm
height of the flask= 12 cm
volume of flask is given by =
putting values and solving we get =396 cm^3
therefore the volume unfilled= 396-200= 196cm^3
therefore % of volume unfilled= 196/396*100= 49.49%
Answer:
y = 20
Step-by-step explanation:
-3y+12 = -48 . -12 from both sides
-3y = -60 . ÷3 on both sides
y = 20
