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Pani-rosa [81]
3 years ago
14

2a. Determine the equation of the line connecting the points (0, -1) and (2, 3) *

Mathematics
1 answer:
Sauron [17]3 years ago
8 0
First create the equation y=Mx+ B

B is the y intercept so when y = 0, B = -1.

Now we have y=Mx - 1

The slope is M. We can calculate this by using the formula M = (y2 -y1) / (x2 - x1)

Use the points (0, -1) and (2,3) for these values. So y2 = 3, y1 = -1, x2 = 2, x1 = 0

Plug them into the equation and solve

M = (3 + 1) / (2 - 0)
M = 4/2 = 2

Now we have the equation y = 2x - 1

Next to figure out if the points given are on the line you take the values and plug them into your equation like so: 4 = 2(-2) - 1

2(-2) - 1 does not equal 4 so this point does not fall on this line. Follow this same procedure for the next point given.
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PLZ HELP ASAP (10 points)
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Answer:

<DAB= 98

Step-by-step explanation:

Remark

I think you are supposed to assume that this is a parallelogram. In that case the two labeled angles are intended to be equal (one of the properties of a parallelogram).

Equation

2x + 36 = 3x - 5                    Add 5 to both sides

2x + 36 + 5 = 3x  - 5 + 5      Combine

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Answer

<DAB = 2x + 36

<DAB = 2*41 + 36

<DAB = 82 + 36

<DAB = 98


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