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Pani-rosa [81]
3 years ago
14

2a. Determine the equation of the line connecting the points (0, -1) and (2, 3) *

Mathematics
1 answer:
Sauron [17]3 years ago
8 0
First create the equation y=Mx+ B

B is the y intercept so when y = 0, B = -1.

Now we have y=Mx - 1

The slope is M. We can calculate this by using the formula M = (y2 -y1) / (x2 - x1)

Use the points (0, -1) and (2,3) for these values. So y2 = 3, y1 = -1, x2 = 2, x1 = 0

Plug them into the equation and solve

M = (3 + 1) / (2 - 0)
M = 4/2 = 2

Now we have the equation y = 2x - 1

Next to figure out if the points given are on the line you take the values and plug them into your equation like so: 4 = 2(-2) - 1

2(-2) - 1 does not equal 4 so this point does not fall on this line. Follow this same procedure for the next point given.
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no solution.

Step-by-step explanation:

1) in order to explain, the given system should be resolved:
\left \{ {{2y=6x+4} \atop {y=3x-4}} \right. \ < = > \ \left \{ {{y=3x+2} \atop {y=3x-4}} \right.

2) the both equations have the same slope (it is 3), it means the given lines are parallel, then no solution.

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