The distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Given the coordinate (15, -21) and the line 5x + 2y = 4
In order to get the point on the line 5x + 2y =4, we can a point on the line
Let x = 0
5(0) + 2y = 4
2y = 4
y = 2
The point (0, 2) is on the line.
Find the distance between the point (15, -21) and (0, 2) using the distance formula

Hence the distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units
Learn more here: brainly.com/question/22624745
Answer:
<h2>
cos 30°= 0.866</h2>
Step-by-step explanation:
Step one:
Applying the SOH CAH TOA principle
assuming all dimensions are in cm
Step two:
Given data
opposite= 1 cm
hypotenuse= 2 cm
<h3>we can now solve for θ</h3>
Sin(θ)= opp/hyp
Sin(θ)= 1/2
Sin(θ)= 0.5
θ= sin-1 0.5
θ= 30°
hence from tables cos 30°= 0.866
Step-by-step explanation:
if you mean the area of the triangle then it is S = 1/2*x(x-7)
Answer:
C
Step-by-step explanation: