Lateral Area, namely the area of its sides, namely excluding its base.
well, the pyramid is standing on one of its triangular faces, so we'll have to exclude that.
now, let's notice, is a square pyramid, so it has an 8x8 square, and it has triangular faces that have a <u>base of 8 and a height of 22</u>.
![\bf \stackrel{\textit{square's area}}{(8\cdot 8)}~~+~~\stackrel{\textit{3 triangular faces' area}}{3\left[ \cfrac{1}{2}(8)(22) \right]}\implies 64+264\implies 328](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bsquare%27s%20area%7D%7D%7B%288%5Ccdot%208%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7B3%20triangular%20faces%27%20area%7D%7D%7B3%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%288%29%2822%29%20%5Cright%5D%7D%5Cimplies%2064%2B264%5Cimplies%20328)
Answer:
do you have a picture of the graph?
Answer:
x=25
Step-by-step explanation:
all you do to find x is subtract 30 from 5 and you get 25 you double check by replacing x for 25 and there is your answer!
Answer:
a = 6
Step-by-step explanation:
(3.14 * 18) * 17.5 = 3.14 * (3a * 17.5)
3.14(3x * 17.5) = (3.14 * 18) * 17.5
3.14(3a * 17.5) = 3.14 * 18 * 17.5
3.14(3a * 17.5) = 989.1
3.14 * 3a * 17.5 * 100 = 989.1 * 100
16485a = 98910
a = 98910/16485
a = 6
