Answer:
B
Step-by-step explanation:
(1 1/2,-2)
solve for x and get 1 1/2
solve for y and get -2
The property shown is a B: substitution property, this is when you you the know that X=Y so X can be substituted in any equation with Y and Y can be substituted in any equation with X. hope this helps
Answer:
We would have

where " l " is length, " w" is width and "h" is height.
Step-by-step explanation:
Step 1
Remember that
Surface area for a box with no top = 
where " l " is length, " w" is width and "h" is height.
Step 2.
Remember as well that
Volume of the box = 
Step 3
We can now use lagrange multipliers. Lets say,

and

By the lagrange multipliers method we know that

Step 4
Remember that

and

So basically you will have the system of equations

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

Then you would get

You can get rid of
from these equations and you would get

And from those equations you would get

Now remember the original equation

If we plug in what we just got, we would have

Answer:
The area of each section of the circle is 
Step-by-step explanation:
we know that
The area of a circle is equal to

we have

substitute

To find the area of each section divide the complete area of the circle by 
so

The scientific notation for the number 1063 is 1.063×10³ after using the concept of fraction option (B) 1.063×10³ is correct.
<h3>What is the number?</h3>
A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.
It is given that:
The number is 1063
As we know the scientific notation can be written as:

1063 can be written as:
= 1063
= (1063/1000)1000
1.063×10³
Thus, the scientific notation for the number 1063 is 1.063×10³ after using the concept of fraction option (B) 1.063×10³ is correct.
Learn more about the number here:
brainly.com/question/17429689
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