Answer:
10th term is 10
Step-by-step explanation:
The nth term for finding the geometric progression is expressed as;
Tn = ar^n-1
a is the first term
r is the common ratio
n is the number of terms
a11 = ar^11-1
a11 = ar^10
Since a11 = -5 and r = -1/2
-5 = a(-1/2)^10
-5 = a(1/1024)
a= 1024 * -5
a = -5120
Nest is to get the 10th terms
a10 = ar^9
a10 = -5120 * (-1/2)^9
a10 = -5120 * -1/512
a10 = 10
Hence the 10th term of the sequence is 10
Answer:
x = ± 7
Step-by-step explanation:
Given
(2x - 1)(3x + 2) = x + 292 ← expand left side using FOIL
6x² + x - 2 = x + 292 ( subtract x from both sides )
6x² - 2 = 292 ( add 2 to both sides )
6x² = 294 ( divide both sides by 6 )
x² = 49 ( take the square root of both sides )
x = ± 7
That is x = - 7, x = 7
The answer is -4. I solved it on a calculator and got -4
Answer:
(a) H0:μ1=μ2; Ha:μ1≠μ2, which is a two-tailed test.
Step-by-step explanation:
We formulate the
H0: μ1=μ2; null hypothesis that the two means are equal and alternate hypothesis that the two mean are not equal.
Ha:μ1≠μ2 Two tailed test
Test statistic used is
t= x1`-x2` / s√n as the variances are equal and sample size is same
T value for 9 degrees of freedom for two tailed test at α = 0.05 is 2.26
P- value for t test for 9 degrees of freedom is 0.125 from the table.
Hence only a is correct .
The missing reason to complete Hector's proof is
<span>Corresponding Parts of Congruent Triangles Are Congruent
It's been established in the previous statement that triangle LNO and triangle PNM are congruent by the AAS Postulate.
The proof
</span>Corresponding Parts of Congruent Triangles Are Congruent
is comprehensive.
