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iren [92.7K]
3 years ago
14

Identify a counterexample to disprove n3 ≤ 3n2, where n is a real number.

Mathematics
2 answers:
Semmy [17]3 years ago
8 0
n^3\le3n^2\iff n^3-3n^2\le0\iff n^2(n-3)\le0

The quantity on the left hand side will be positive for any n>3, so suppose consider n=4.

Now,

4^3=64

but

3(4)^2=48

and 64\not\le48
dem82 [27]3 years ago
5 0
n^3-3n^2\ \leq   \ 0    \text{Move all terms to one side} 

n^2(n-3) \leq0   \text{Factor out the common term} \  {n}^{2} 

n(n-3) = 0  \text{when n=0,3} 

⇒ \text{From the values of} \ n^2 \text{ above, we have these 3 intervals to test} 

⇒ n \leq0 

⇒ 0 \leq   n \leq  3 

⇒ n \geq  3

⇒ \text{Pick a test point for each interval} 


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