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iren [92.7K]
3 years ago
14

Identify a counterexample to disprove n3 ≤ 3n2, where n is a real number.

Mathematics
2 answers:
Semmy [17]3 years ago
8 0
n^3\le3n^2\iff n^3-3n^2\le0\iff n^2(n-3)\le0

The quantity on the left hand side will be positive for any n>3, so suppose consider n=4.

Now,

4^3=64

but

3(4)^2=48

and 64\not\le48
dem82 [27]3 years ago
5 0
n^3-3n^2\ \leq   \ 0    \text{Move all terms to one side} 

n^2(n-3) \leq0   \text{Factor out the common term} \  {n}^{2} 

n(n-3) = 0  \text{when n=0,3} 

⇒ \text{From the values of} \ n^2 \text{ above, we have these 3 intervals to test} 

⇒ n \leq0 

⇒ 0 \leq   n \leq  3 

⇒ n \geq  3

⇒ \text{Pick a test point for each interval} 


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Please help mee pleaseee
nalin [4]

Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

-3y = -7-8 ... subtract 8 from both sides

-3y = -15

y = -15/(-3) ... divide both sides by -3

y = 5

-----------

Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

x^3 = 3125

x = \sqrt[3]{3125} Apply cube root to both sides

x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

x = 5*\sqrt[3]{25}

x \approx 14.62009

4 0
3 years ago
Read 2 more answers
I need help!<br><br>solve for x​
Volgvan

Answer:

x = 40

Step-by-step explanation:

Here's a fun fact, all of those angles actually add up to 360 degrees!

How do we know this? Well if you were to draw a small arc between each of the lines, you would see that the arc would end up making a circle. And remember, circles have 360 degrees!

Now we can do some basic algebra. Add up all the angles and set that equal to 360.

(2x) + (x) + (3x + 20) + (2x+20) = 360.

8x + 40 = 360

8x = 320

x = 40

Hope this helped!

4 0
2 years ago
jordan has 90 photos.explain three ways he can arrange the photos in his album so he has the same number of photos on each page
erik [133]

Answer:

Divide the number of pages in the album by the 90 photos

Place one photo on a page at a time then start over when he reaches the end of the album and continue to repeat until all photos are gone

Just have one page of photos




Step-by-step explanation:


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3 years ago
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Compare the values of the 5s in the number 1.055
lianna [129]

Answer:

50 + 5

Step-by-step explanation:

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2 years ago
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THERES NO MATH SO I CANT ANSWER YOUR QUESTION
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