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Mariulka [41]
3 years ago
11

Help me with this please

Mathematics
1 answer:
salantis [7]3 years ago
8 0
Can’t see the image!
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Help thanks//////////??????????
3241004551 [841]

Answer:

Step-by-step explanation:

At the point where two line cut across, the vertically opposite angles formed are equal. This means that

2x degrees = 78 degrees

Dividing the left hand side and the right hand side of the equation by 2, it becomes

2x/2 = 78/2

x = 39

Checking,

The sum of the angles on a straight line is 180 degrees.

180 - 78 = 102 degrees

2x + 102 = 180

2x = 180 - 102 = 78

x = 78/2 = 39

8 0
3 years ago
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Find the missing side. Round to the nerest tenth.
Art [367]

Answer: theres no pic?

Step-by-step explanation:

3 0
2 years ago
What is the distance between -2/3 and 4/3 on a number line?
soldier1979 [14.2K]
If from the negative to the positive side, count how many dots are in between and add together. So it is 6 units apart or 6 dots apart.
8 0
2 years ago
The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin
quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

5 0
3 years ago
Please help 50 points!<br> Simplify the expressed
LenKa [72]

Answer:

Step-by-step explanation:

\frac{x^{2} -x-12}{x+4} * \frac{2x^{2}-32 }{x^{2} -8x+16}  rewrite as multiplication

\frac{x^{2} +3x-4x-12}{x+4} * \frac{2(x^{2}-16) }{x^{2} -8x+16}  look to factor

\frac{x(x+3)-4(x+3)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}  , difference of 2 squares and perfect square

\frac{(x+3)(x-4)}{x+4} * \frac{2(x-4)(x+4) }{(x-4)^{2}}, finish factoring and simplify

2(x+3)

3 0
2 years ago
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