A. Click on any cell in the row
Answer:
C. Trojan
Explanation:
In Cybersecurity, vulnerability can be defined as any weakness, flaw or defect found in a software application or network and are exploitable by an attacker or hacker to gain an unauthorized access or privileges to sensitive data in a computer system.
This ultimately implies that, vulnerability in a network avail attackers or any threat agent the opportunity to leverage on the flaws, errors, weaknesses or defects found in order to compromise the security of the network.
In this scenario, a security administrator is reviewing the following information from a file that was found on a compromised host: "cat suspiciousfile.txt."
Some of the ways to prevent vulnerability in a network are;
1. Ensure you use a very strong password with complexity through the use of alphanumerics.
2. You should use a two-way authentication service.
3. You should use encrypting software applications or services.
Answer:
- def Lambda(strList):
- return list(filter(lambda s: (s.startswith("e")), strList))
-
- print(Lambda(["meaning", "cart", "engine", "egg"]))
Explanation:
The solution code is written in Python 3.
Lambda function is an anonymous function. It is a function without any name and it is started with keyword lambda. To write a lambda function to filter the string started with an 'e', we can write a lambda expression, s.startswith("e") that work on one input strList. If any word from strList started with letter "e", the word will be added into a list generated by filter function. At the end, the Lambda function will return the list of strings as output.
When we test the Lambda function using the sample string list (Line 4), we shall get ['engine', 'egg'] printed to terminal.
Yes , it’s true. In a known-plaintext attack (kpa), the cryptanalyst can only view a small portion of encrypted data, and he or she has no control over what that data might be.
The attacker also has access to one or more pairs of plaintext/ciphertext in a Known Plaintext Attack (KPA). Specifically, consider the scenario where key and plaintext were used to derive the ciphertext (either of which the attacker is trying to find). The attacker is also aware of what are the locations of the output from key encrypting. That is, the assailant is aware of a pair. They might be familiar with further pairings (obtained with the same key).
A straightforward illustration would be if the unencrypted messages had a set expiration date after which they would become publicly available. such as the location of a planned public event. The coordinates are encrypted and kept secret prior to the event. But when the incident occurs, the attacker has discovered the value of the coordinates /plaintext while the coordinates were decrypted (without knowing the key).
In general, a cipher is easier to break the more plaintext/ciphertext pairs that are known.
To learn more about Plaintext Attack click here:
brainly.com/question/28445346
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