Ask question

Ask question

All categories

4 years ago

6

Bennett spent 4 hours at school today. He attended three 70-minute classes. There is a 5-minute break between classes. Then he a

te lunch before going home. How long did Bennett spend eating lunch?

1 answer:

nasty-shy [4]4 years ago

4 0

Answer:

20 minutes

Step-by-step explanation:

70 minute classes times 3

Plus 2 breaks one in between 1st and 2nd class

And another in between 2nd and 3rd class

Which = 220 minutes

4 hours times 60 (because 60 minutes per hour)

Gives us 240 minutes

Then you subtract total time from time in classes and breaks

Which gives us 20 minutes for lunch time

You might be interested in

Please help asap... I have no clue how to do this

Fed [463]

Answer:

50th term is 164

Step-by-step explanation:

a(n) = 17 + 3(n - 1)

a(50) = 17 + 3(50-1)

a(50) = 17 + 3(49)

a(50) = 17 + 147

a(50) = 164

3 0

3 years ago

For every 8 boys signed up for intramural basketball, there are 6 girls. If there are 60 girls signed up to play intramural bask

harkovskaia [24]

Answer is 80

6 x 10 = 60

8 x 10 = 80

brainliest?

7 0

2 years ago

Read 2 more answers

It keeps saying my answer is wrong

mariarad [96]

Since the formula is $\frac{1}{2}h(B1+B2)$ , here's the answer.

First we do $\frac{1}{2}10$ , which gives us 5.

Then we do $5(20+8)$ , which gives us $5(28)$ .

At last we do $5*28$ , and we get 140.

So, the answer would be 140.

Hope this helped! c:

4 0

3 years ago

Part A: The decimal form of the rational number 3/40 is

Gnom [1K]

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c | } \\ \bf{Part \: A} & \bf \footnotesize{The \: decimal \: form \: of \: the \: rational \: number \: \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}} \\ \\ \hline \\ \bf{Part \: B}& \: \bf \footnotesize{The \: value \: of \: \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \\ \\ \hline \\ { \bf Part \:C \: }& \: { \bf\footnotesize{On \: simplifying \: \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. \: \: \: \: \: \: \: \: }} \\ \\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

$\bf \underline{Answer-} \\$

${ \bf{Part \: A \: | \: \footnotesize{The \: decimal \: form \: of \: the \: rational \: number \: \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}}}}$

${ \bf{Part \: B \: | \: \footnotesize{The \: value \: of \: \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3 }}}$

$\bf \underline{Step \:by \:step\: Explanation-} \\$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \sqrt[4]{(9)^{ - 2} } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \sqrt[ \cancel4]{(9)^{ \cancel{ - 2}} } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \sqrt{9^{ - 1} } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ {3}^{ - 1 } }}$

${ \sf \: \: \: \: \: : \: \: \implies\dfrac{1}{ \dfrac{1}{3} }}$

${ \sf \: \: \: \: \: : \: \: \implies3}$

${ \bf Part \:C \: } | \: { \bf\footnotesize{On \: simplifying \: \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. }}$

${~~~\sf ~~:~~\implies (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7})}$

${~~~~\sf ~:~~\implies 5+ \cancel{3 \sqrt{7}} + 12 \cancel{ - 3 \sqrt{7}}}$

${~\sf ~~~~:~~\implies 17}$

$\underline{\rule{200pt}{2.5pt}}$

8 0

3 years ago

-4y-2y^3-4+4y+5-2-2y^3−4y−2y3−4+4y+5−2−2

aniked [119]

Answer:

4y=123_2y=320

Step-by-step explanation:

3 0

4 years ago