The horizontal distance is given by the formula:
tan θ=opposite/adjacent
where:
θ=21
opposite=2000 ft
adjacent=a
thus calculating for a we get:
tan 21=2000/a
thus
a=2000/tan 21
a=5210.18 ft
Answer: 5210.18 ft
Answer:
A(t) = amount remaining in t years
= A0ekt, where A0 is the initial amount and k is a constant to be determined.
Since A(1690) = (1/2)A0 and A0 = 80,
we have 40 = 80e1690k
1/2 = e1690k
ln(1/2) = 1690k
k = -0.0004
So, A(t) = 80e-0.0004t
Therefore, A(430) = 80e-0.0004(430)
= 80e-0.172
≈ 67.4 g
Step-by-step explanation:
g(x) is a shift of 8 units to the left and 4 units of f(x), then the correct statement is B.
<h3>
Which statement compares the graph of the two functions?</h3>
First, a vertical shift of N units is written as:
g(x) = f(x) + N
- if N > 0 the shift is upwards.
- If N < 0 the shift is downwards.
A horizontal shift of N units is written as:
g(x) = f(x + N).
- if N < 0, the shift is to the right.
- If N > 0, the shift is to the left.
In this case, we have:
g(x) = f(x + 8) + 4
So g(x) is a shift of 8 units to the left and 4 units of f(x), then the correct statement is B.
If you want to learn more about translations:
brainly.com/question/24850937
#SPJ1
I hope this helps you
1)
f (2)=2.2^2-3.2-7
f (2)=8-6-7
f (2)= -5
2)
f (2)=2.2^2-3.2+7
f (2)=8-6+7
f (2)=9
Well, to find out whether she spent more time getting dressed or eating breakfast, we simply have to compare the fractions of the hour that she took on each.
We know that she took 3/6 of an hour to get dressed and 1/4 of an hour to eat breakfast. To find out which activity she spent more time on, we simply need to see which fraction is bigger.
To do this, we must first reduce the fractions to lowest terms. 1/4 is already in lowest terms, so we can leave that alone. 3/6 can be reduced, however, and since 3 goes into 6 twice, it reduces to 1/2.
Now, we can compare the fractions.
Is 1/2 of an hour or 1/4 of an hour more?
The answer is 1/2, so now we know that Bailey spent more time getting dressed than eating breakfast.
Hope that helped! =)
