Answer: the answer to this is 9/10
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
Answer:
they both has 7 slides and the presentation had a duration of 28 seconds
Step-by-step explanation:
we have to setup equation that makes them equal to each other if you know what i mean. 2x+16=3x+10
then we just solve for x
2x+16=3x+10
subtract 10 from each side
2x+6=3x
step 2 subtract 2x from each side
x=6
so both of their presentations are 7 slides long
then to find the length of their presentations we just plug in 6 to one of the equations
2(6)+16
2x6=12 12+16=28 so both of their presentations were 28 seconds
<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? </h3>
<em>First we have to find the factors of 15x³y²</em>
<em>15x³y² = 3 * 5x³y² </em>
<em>Then we have to find the factors of 20x⁴y⁴</em>
<em>20x⁴y⁴ = 2²x¹y² * 5x³y²</em>
<em>Now we have to find the common factors to both numbers.</em>
<em>The common factors are </em><em>5x³y²</em>
Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²
Hope this helps!
Step-by-step explanation:
1 m = 100 cm So
48 × 100 = 4800 cm
1m = 1000mm
456 mm into m
= 456 ÷ 1000
= 0.456 m