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marshall27 [118]
3 years ago
9

The chart below shows the cost of the three different-sized boxes of chicken nuggets that are available at The Chicken Shack.

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0

So, by plugging in 1.25/5, 2.07/9, and 3.15/15, I got 0.25, 0.23, and 0.21, respectively.

So if you're trying to find the least amount cost per nugget, then 0.21 from the large box option would be your answer.

Semmy [17]3 years ago
3 0

Answer:0.21 the large box

Step-by-step explanation: find unit rate for each box.

$1.25/5=$.25 - small

$2.07/9=$.23 - medium

$3.15/15=$.21 - large

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PLZ ANSWER THE QUESTION FROM THE PICTURE ASAP <br>20 POINTS ​
almond37 [142]

Answer:

Step-by-step explanation:

The recursive rule is given by;

a = r .an-1 where n is the number of terms.

Given the sequence: -64, -16, -4 , -1, ....

This sequence is a geometric sequence with common ratio (r) = 1/4

Here, first term a1 = -64

Since,

\frac{-16}{-64} = \frac{1}{4}

\frac{-4}{-16} = \frac{1}{4} and so on....

The recursive rule for this sequence is;

an = 1/4*an-1

8 0
3 years ago
An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} =  \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet

The arrow will hit the target 1.84feet below the bullseye.

5 0
3 years ago
A fruit stand has to decide what to charge for their produce. They need $5.30 for 1 apple and 1 orange. They also need $7.30 for
Aneli [31]

Answer:

A fruit stand has to decide what to charge for their produce.

They need $ 5.30 for 1 apple and 1 orange.

They also need $ 7.30 for 1 apple and 2 oranges.

TO DETERMINE

To put this information into a system of linear equations.

TO find a unique price for an apple and an orange

EVALUATION

Let the price of an apple = x and price of an orange = y

So From the first condition that they need $ 5.30 for 1 apple and 1 orange we get

\sf{x + y = 5.30}x+y=5.30 - - - - Equation 1

Again from second condition that they need $ 7.30 for 1 apple and 2 oranges we get

\sf{x + 2y = 7.30}x+2y=7.30 - - - - Equation 2

So the required Set of linear equations are

x + y = 5.30

x + 2y = 7.30

Equation (2) - Equation (1) we get

y = 2

From Equation (1) we get

x = 5.30 - 2 = 3.30

Hence price of an apple = $ 3.30

The price of an orange = $ 2

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2 years ago
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