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3 years ago

Based on the diagram to the right,what will happen to the motion of the box?Select two that apply.

Mathematics

1 answer:

Andrej [43]3 years ago

5 0

The box should move east

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Rani scores 4 times as many baskets as Layla. Tash scores 8 baskets less than Rani. They score 100 baskets in total. How many ba

Sever21 [200]

Answer:

Tash scores 40 baskets

Step-by-step explanation:

Rani = R

Layla = L

Tash = T

R = 4L

T = 4L-8

As L + R + T = 100

L + 4L + 4L-8 = 100

Collect like terms

9L - 8 = 100

+ 8 both sides

9L = 108

divide by 9 both sides

L = 108 / 9

L = 12

Now..... T = 4L-8 substitute L with 12

T = 48 - 8

T = 40

8 0

3 years ago

Please be quick i dont have that much time

Oduvanchick [21]

Answer:

To find the sum of interior angles in a polygon, we can use the formula:

$180(n-2)$ where n is the number of sides.

Since this is pentagon (5 sides), then $180(5-2)=180*3=540$

The missing angle would then be

$540-97-111-104-115=113$

Since angles on a straight line add up to 180, then

$x+113=180$

$x=67$

3 0

2 years ago

49.5 is what percent of 33

kap26 [50]

Your answer would be 49.5 is 150% of 33.

7 0

3 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

1 year ago

SOLVE FOR X PLEASEE HELP

Ivenika [448]

To solve this, you will have to set up your equation as fractions:

X is to 4 as 4 is to 4+3, or 7

X/4 = 4/7

You will then cross multiply

7x = 4•4
7x = 16

Divide.

X = 2.285714...

Round to the nearest hundredth.

2.29

3 0

3 years ago