Help me with 1 2 and 3 please

Mathematics

1 answer:

barxatty [35]3 years ago

5 0

Answer:

1. (-2,2) 2.(1,2) 3. B&A

Step-by-step explanation:

You might be interested in

What is the mean of the data ?

julia-pushkina [17]

Answer:

maryland

Step-by-step explanation:

3 0

3 years ago

What is the probability that when we roll 5 fair 6-sided dice, at most 4 of them will show a 1?

lions [1.4K]

If you're rolling 5 dice, and all dice have a 1 on them, then you still have a 4/5 chance that four of the five dice will show 1.

4 0

3 years ago

In the expression 3x² + y − 5, which of the following choices is the exponent in the term 3x²?

quester [9]

Answer: the exponent would be the 2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

Let $\bar X$ = sample mean heights

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)