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3 years ago

Hey I need this quick

Mathematics

2 answers:

Citrus2011 [14]3 years ago

6 0

Answer:

Step-by-step explanation:

go over 5 on the x axis and go up 1 on the y axis

Tems11 [23]3 years ago

5 0

Answer:

Step-by-step explanation:

A is at 5,1 so this would make sense

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Combine the like terms

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6x-7+6x³-4x-10x³-4-8x - 2x²= −43−22−6−11

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8u+6+7u+(-10) + (-5u) + 8= 10+4

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3 years ago

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What is the absolute value of -90?

Alexandra [31]

Answer: 90

Step-by-step explanation:

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3 years ago

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please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

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3 years ago

Please help this is due soonnnnn

Makovka662 [10]

Answer:

5 $\sqrt{14r}$ - $\sqrt{42r}$ / 28r

sorry I can't put a fraction but the "'/" is the line and 28r goes underneath

Explanation:

Download photomath and take a picture, it will explain it. It would take forever for me to type it out

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3 years ago

What is 23 divided by 99 in decimal form

Yuki888 [10]

I think it would be 0.23 repeating so basically 0.23232323

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3 years ago

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Hey I need this quick​

Hey I need this quick