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mr_godi [17]
3 years ago
14

ANSWER the MATH problem if you love yo mama (ill give brainliest)

Mathematics
2 answers:
kogti [31]3 years ago
5 0

Answer:

The first one is 7 and the second one is 8.

Step-by-step explanation:

Cerrena [4.2K]3 years ago
4 0

Answer:

The answer is 9

Step-by-step explanation:

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"Given m = -2/5 and b = -7, write the equation of the line containing these points"
KatRina [158]

Answer:  y = (-2/5)x - 7

This is the same as writing y = -\frac{2}{5}x-7

======================================================

Explanation:

Any linear equation is of the form y = mx+b, known as slope-intercept form

m = slope

b = y intercept

We'll replace m with -2/5 and replace b with -7 to get y = (-2/5)x + (-7) which simplifies to y = (-2/5)x - 7

4 0
2 years ago
The graph of r = -3 + 5cos(theta) is symmetric about the __________.
bonufazy [111]

Answer: B

Step-by-step explanation:

X axis only

5 0
3 years ago
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Find the product.<br><br> -7(-a^2)(-b^3)
Reil [10]
I belive the answer to your question would be -7a^2b^3

4 0
4 years ago
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0.091hm convert it's height in meter<br>(explanation)​
yarga [219]

Answer:

9.1

Step-by-step explanation

1 hm = 100m

0.091 * 100 = 9.1

8 0
3 years ago
A(3,4),B(5,8),C(7,8) are the vertices of ABC, prove that the line passing through the mid point of AB and AC is parallel to BC
Ede4ka [16]
<h2>Explanation:</h2><h2></h2>

The \ midpoint \ formula \ of \ the \ line \ segment \\ that \ joins \ the \ two \ points \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ is \\ given \ by \ the \ following \ Midpoint \ Formula:\\ \\ Midpoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

<h2></h2>
  • Let's name the mid point of AB as c
  • Let's name the mid point of AC as p

Then:

c=(\frac{3+5}{2},\frac{4+8}{2}) \\ \\ c=(\frac{8}{2},\frac{12}{2}) \\ \\ c=(4,6) \\ \\ \\ p=(\frac{3+7}{2},\frac{4+8}{2}) \\ \\ p=(\frac{10}{2},\frac{12}{2}) \\ \\ p=(5,6)

So the slope of the line that passes through c \ and \ p is:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ m_{cp}=\frac{6-6}{5-4}=0

And the slope for BC is:

m_{BC}=\frac{8-8}{7-5}=0

As you can see, both slopes are zero, so these are horizontal lines.

5 0
4 years ago
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