3. f(-6) = 12+1 =13
f(-2) = 4+1 = 5
f(0) =1
Range {1,5,13}
4. f(-2) = (-2)^3+1 =-7
f(-1) = (-1)^2 +1 =0
f(3) = (3)^3 +1 = 28
Range = {-7,0,28}
5.the sequence is arithmetic
d= -11+19 = 8
an = a1 + d(n-1)
an = -19 +8(n-1)
6.l =w+5
a =l*w
a(w) =(w+5) * w
a(w)= w^2 +5w
f(w) = w^2 +5w
f(8) = 8^2 +5(8)
f(8) = 64 +40
f(8) =104 in^2
Answer:
x = ± 4
y = - 2
Step-by-step explanation:
y = 0.5x² - 10 ------------------------(I)
y = -x² + 14 ------------------------(II)
Substitute the y value in equation (II)
0.5x² - 10 = -x² + 14 {Add x² to both sides}
0.5x² + x² -10 = 14 {combine like terms}
1.5x² - 10 = 14 {Add 10 to both sides}
1.5x² = 14 + 10
1.5x² = 24 {Divide both sides by 1.5}
1.5x²/1.5 = 24/1.5
x² = 16
x = ±4
Substitute x = 4 in (I)
y = 0.5 * 4² - 10
= 0.5*16 - 10
= 8- 10
y = -2
Substitute x = -4 in (I)
y = 0.5 * (-4)² - 10
= 0.5*16 - 10
= 8- 10
y = -2
Answer:
0
Step-by-step explanation:
product is another word for +
decreased is another word for -
____________________________
(7 + 8) - x
so
(7+8) - 15
15 - 15
= 0
