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3 years ago

Which angle is complementary to <ADB?

Mathematics

2 answers:

nordsb [41]3 years ago

6 0

D is the correct answer

m_a_m_a [10]3 years ago

3 0

Answer:

Angle CDA IS CORRECT

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Question is in the picture. Please help

irakobra [83]

BD = AC Given. BD cuts AC in half. That's what bisectors do.

BD = BD Reflexive property of a line (it is always equal to itself).

<ADB = <ADC = 90o

DB is perpendicular to AC Given.

<ADB + <ADC = 180o The two are supplementary.

Each angle = 90o Perpendicular means that one line meets another at 90o

2x = 180

x = 90o

Since each of the enclosed angles = 90, two have two triangles congruent by SAS <<<< Answer

4 0

3 years ago

Kelly Slater and Andy Irons are in a surf competition among 10 competitors.

Delvig [45]

Answer:

The probability that Kelly will place 1st and Andy will place 2nd is 1/90, or 1.11%.

Step-by-step explanation:

Since Kelly Slater and Andy Irons are in a surf competition among 10 competitors, to determine, if all surfers are at an equal surfing level, then what is the probability that Kelly will place 1st and Andy will place 2nd, the following calculation must be performed:

1/10 x 1/9 = X

0.1 x 0.11 = X

0.01111 = X

1/90 = 0.011111 = X

Therefore, the probability that Kelly will place 1st and Andy will place 2nd is 1/90, or 1.11%.

5 0

2 years ago

Can someone please help me

viktelen [127]

The surface area Is 98

8 0

3 years ago

The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is $y=\frac{1}{3}x$

7 0

3 years ago

Read 2 more answers

The triple of the sum of two consecutive numbers is 99. Which is the greater of the two numbers.

san4es73 [151]

Answer:

I have no idea Im so sorry i tried to understand all i could think of is x+y=99

3 0

3 years ago