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3 years ago

Which angle is complementary to <ADB?

Mathematics

2 answers:

nordsb [41]3 years ago

6 0

D is the correct answer

m_a_m_a [10]3 years ago

3 0

Answer:

Angle CDA IS CORRECT

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The variables x and y vary inversely If x=5 when y=12, then find the value of x when y=32

Vilka [71]

Answer:

x=15/8

Step-by-step explanation:

Inverse variation is given by

xy = k

Substituting x=5 and y=12

5*12 = k

60 =k

Our original equation is xy = 60

Now let y=32

x*32 = 60

Divide each side by 32

32x/32 = 60/32

Divide top and bottom by 4

x = 15/8

4 0

3 years ago

How many solutions does the system have? \begin{cases} 5y =15x-40 \\\\ y = 3x-8 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ 5y=15x−40 y=3x−8 C

Ksenya-84 [330]

Answer:

Step-by-step explanation:

Converting the lines into the from $ax+by+c=0$

$5y=15x-40\\\Rightarrow 15x-5y-40=0$

$y=3x-8\\\Rightarrow 3x-y-8=0$

$\dfrac{a_1}{a_2}=\dfrac{15}{3}=5$

$\dfrac{b_1}{b_2}=\dfrac{-5}{-1}=5$

$\dfrac{c_1}{c_2}=\dfrac{-40}{-8}=5$

So, $\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$ .

Hence, these lines have infinitely many solutions.

3 0

2 years ago

Height is 6.2cm length is 10.8cm what’s the area.

mariarad [96]

Answer:

its 66.96

Step-by-step explanation:

to find the area we do the length x height of the shape

3 0

2 years ago

Read 2 more answers

Haley draws one card from a standard deck of 52 playing cards. She draws one card, returns it to the deck, shuffles the deck, an

ipn [44]

Answer:

Step-by-step explanation:

because of the square she drawn

3 0

3 years ago

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

Step 1:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

step 2:-

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

verification:-

$AC^2 = AB^2 + BC^2$

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

3 years ago

Read 2 more answers