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3 years ago

Which of the following equations is equivalent to

Mathematics

1 answer:

sveticcg [70]3 years ago

6 0

Answer:

I think the answer is c

Step-by-step explanation:

sorry if it's wrong

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Factorise 2-y(7-5y) please

hjlf

Answer:
(y - 1)(5y - 2)

Solution:

Factor:
2 - y(7 - 5y)

Apply the Distributive Property:
2 - 7y + 5y²

Reorder the expression:
5y² - 7y + 2

Rewrite the term:
5y² - 5y - 2y + 2

Regroup terms into two proportional parts:
(5y² - 5y) + ( -2y + 2)

Factor Greatest Common Factors out:
5y(y - 1) - 2(y - 1)
(y - 1)(5y - 2)

5 0

2 years ago

Please help 25 points and brainlist if right.

Nina [5.8K]

6. 5. That’s the answer hope it helps

4 0

2 years ago

Read 2 more answers

A student can type 65 words in 2 minutes. How many words can student tupe in 20 minutes?

saul85 [17]

650 Because if the student can do 65 words in 2 mins, you would have to do 20 divided by 2 and get 10 then times 10 by 65 which is 650 in 20 mins.

6 0

3 years ago

Read 2 more answers

Ibrahim cuts the grass for several of his

REY [17]

Answer:

5 gallons per week

Step-by-step explanation:

He uses 1.25 gallons per 5 hrs

How many times does he use a full tank in a week?

20/5 =<u> 4 times</u>

To find the total amount of fuel used take 1.25 times 4

1.25 * 4 = 5 gallons

3 0

3 years ago

A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m

Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The width of the interval is:

$W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an $\pi$

Interval A:

9000 viewers.

So the width is

$W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}$

Interval B:

100 viewers

So the width is

$W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}$

Relationship between the widths:

$R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0

3 years ago