$\frac{3x-1}{x-2}=x-2x(x-4) \frac{3x-1}{x-2}=x-2x^{2} +8x \\\frac{3x-1}{x-2}=-2x^{2} +9x3x-1= (-2x^{2} +9x)(x-2)\\3x-1= -2x^3+4x^{2} +9x^{2} -18x\\3x-1=-2x^3+13x^{2} -18x\\2x^3 -13x^{2} +18x+3x -1=0\\2x^3 -13x^{2}+21x-1=0\\ x =0.05 /or/x=3.7$

ok done. Thank to me :>

6 0

3 years ago

I’m stuck on these questions

jolli1 [7]

Answer:

In my opinion both of the lines are tangent.

Step-by-step explanation:

Because a tangent to a circle is a straight line which touches the circle at only one point. This point is called the point of tangency. The tangent to a circle is perpendicular to the radius at the point of tangency.

5 0

3 years ago

Product of prime numbers in exponential form

love history [14]

A numeric form using exponents.

3 0

4 years ago