IN THE FIGURE 5.24 TO THE RIGHT ABCD IS A RHOMBUS.SHOW THAT AC IS THE BISECTOR OF <BAD.

Mathematics

1 answer:

Inessa05 [86]3 years ago

4 0

In any rhombus, the four sides are the same length.

Because of this, we know that

AD = AB
CD = BC

Furthermore, AC = AC due to the reflective property

Those three facts then allow us to prove triangle ACD is congruent to triangle ACB through the SSS congruence property. Then from CPCTC, we then know that angle DAC = angle BAC, which is enough to show that AC bisects the angle shown. The term "bisect" means "cut in half".

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Find the area A of the sector of a circle of radius 90 in formed by central angle 1/6 radian.

miv72 [106K]

Answer:

2121 $in^{2}$ Rounded to the nearest inch.

Step-by-step explanation:

A = $\pi r^{2}$ Is the formula for a circle, but we only have a portion of a circle so we will have to adjust the formula for a part of the circle.

A = $\frac{\frac{\pi }{6} }{2\pi }$ $\pi r^{2}$ The $\frac{\pi }{6}$ is the part of the circle and the whole circle is 2 $\pi$

$\frac{\frac{\pi }{6} }{2\pi }$ is the same as $\frac{\pi }{6}$ ÷ $\frac{2\pi }{1}$ Which is the same as $\frac{\pi }{6}$ x $\frac{1}{2\pi }$ Which is the same a $\frac{1}{12}$