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4 years ago

11

HELP PLEASE!!!!!!!! 10 points

1 answer:

Elden [556K]4 years ago

8 0

Answer:

pls explain the question properly

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Carbon-141414 is an element that loses about 10\%10%10, percent of its mass every millennium (i.e., 100010001000 years). A sampl

Eduardwww [97]

Answer:

S(t) = 600*0.9^t

Step-by-step explanation:

At the beginning (t = 0) the sample has 600 grams. After 1 millennium from today (t = 1) the mass will be: 600 - 600*0.1 = 600*0.9. After 2 millennium from today (t = 2) the mass will be the 90% of the mass in the previous millenium, that is: 600*0.9*0.9 = 600*0.9^2. Analogously, at time = 3, sample's mass will be: 600*0.9^2*0.9 = 600*0.9^3. In a table format, that is

t m

0 600

1 600 - 600*0.1 = 600*0.9

2 600*0.9*0.9 = 600*0.9^2

3 600*0.9^2*0.9 = 600*0.9^3

Therefore, sample's mass in grams, S(t), where t refers to millennia from today is computed as follows: S(t) = 600*0.9^t

7 0

3 years ago

YES OR NO<br><br> PLEASE HELP MEE THANK YOUUU

qwelly [4]

Answer:

yes

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

A 4-foot tall child walks directly away from a 12-foot tall lamppost at 2 mph. How quickly is the length of her shadow increasin

xz_007 [3.2K]

Answer:

The length of the shadow is increasing with the rate of 1.5 feet per sec

Step-by-step explanation:

Let AB and CD represents the height of the lamppost and child respectively ( shown below )

Also, let E be a point represents the position of child.

In triangles ABE and CDE,

$\angle ABE\cong \angle CDE$ ( right angles )

$\angle AEB\cong \angle CED$ ( common angles )

By AA similarity postulate,

$\triangle ABE\sim \triangle CDE$

∵ Corresponding sides of similar triangles are in same proportion,

$\implies \frac{AB}{CD}=\frac{BE}{DE}$

We have, AB = 12 ft, CD = 4 ft, BE = BD + DE = 6 + DE,

$\implies \frac{12}{4}=\frac{6+DE}{DE}$

$12DE = 24 + 4DE$

$8DE = 24$

$DE=3$

Now, the speed of walking = 2 mph = $\frac{2\times 5280}{3600}\approx 2.933\text{ ft per sec}$

Note: 1 mile = 5280 ft, 1 hour = 3600 sec

Thus, the time taken by child to reach at E

$= \frac{\text{Walked distance}}{\text{Walking speed}}$

$=\frac{6}{2.933}$

= 2.045 hours

Hence, the change rate in the length of shadow

$= \frac{\text{Length of shadow}}{\text{Time taken}}$

$=\frac{3}{2.045}$

= 1.5 ft per sec.

3 0

3 years ago

Number five please show your work

Goryan [66]

Answer:

4 vases will have 4 flowers

The drawing will help

5 0

4 years ago

Read 2 more answers

Who is correct what error did the other person make ?

S_A_V [24]

Concurring that the other one made a mistake.

5 0

3 years ago