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VMariaS [17]
2 years ago
7

Show that y2+ x-3 =0 is an implicit solution to dy/dx =-1/ (2y) on the interval (- [infinity] , 3)

Mathematics
1 answer:
Sedaia [141]2 years ago
4 0

Answer:

Implicit function

\frac{d y}{d x} = \frac{-1}{2y}

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given  y² + x - 3=0 ...(i)

Differentiating equation (i) with respective to 'x', we get

                   2 y \frac{d y}{d x} +1 = 0

           ⇒     2 y \frac{d y}{d x} = -1

           ⇒     \frac{d y}{d x} = \frac{-1}{2y}

                 \frac{d y}{d x} = \frac{-1}{2 (3)}

                 \frac{d y}{d x} = \frac{-1}{6}

 

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Add at least 2 ways people in this job use arts and music ( that job is a dancer btw)
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Answer:

arts: movement and flexibility  Music: communication and rhythm

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2 years ago
What is 2x + 3y&lt; =543 +3x&gt; 3,456,789&lt;12+12+12+12+12+12+12+12+18+19+10+19
artcher [175]

Answer:

65.434

Step-by-step explanation:

4 0
2 years ago
Which transformation maps the pre-image to the image?
Ede4ka [16]

Answer:

Reflection

Step-by-step explanation:

Because reflecting yourself in a mirror means pre image to image

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2 years ago
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

6 0
2 years ago
Find the measure of each bolded arc. Round to the nearest hundredth
vladimir1956 [14]

Answer:

Arc Length = 68.7

Step-by-step explanation:

The formula that is used to find the arc length:

s = (θ/360) * 2πr

(You would get the value of θ, by subtracting 57 from 360)

(You would get r by dividing 26 by 2)

Now we can solve this;

s = (303/360) 2π(13)

s = 0.842 * 2π(13)

s = 0.842 * 0.283(13)

s = 68.7

Hope this helps!

5 0
3 years ago
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