Answer:
Hence average rate of change is greater for f(x) in (0,3).
Yes. f(x) is greater than g(x) in the interval (0,3)
Yes. g(3) <f(3)
Step-by-step explanation:
To find average rate of change of f and g in (0,3)
f(3)-f(0)/3 = (9-0)/3 =3
g(3) = -9-18 = -27
g(0) = 0
Rate of change in(0,3) of g(x) = -27/3 =-9
Hence average rate of change is greater for f(x) in (0,3)
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Both f and g have intercepts of y as 0
Hence both are equal.
3) Yes. f(x) is greater than g(x) in the interval (0,3)
Because g(x) <0 for all x in (0,3) while f(x) >0
4) g(3)= -9-18=-27 <f(3)
(5^-2 ● 4^-4)^-2
you need to multiply tge power of tge outside the bracket with tge power inside the bracket to eliminate the power
= 5^4 ● 4^8
the answer is A
Answer:
x = 10
Step-by-step explanation:
3x - 5 = 2x + 5
3x - 5 + 5 = 2x + 5 + 5
3x = 2x + 10
3x - 2x = 2x - 2x + 10
1x = 10
x = 10
You could just subtract the numbers from the line. It's simple.
Area is 92.13 and the perimeter is 47.42 i think it’s correct
