Step-by-step explanation:
tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)
= (sin2B + cos2B)/[(cosB)(sinB)]
= 1/[(cosB)(sinB)]
= (1/cosB)(1/sinB)
= (secB)(cscB)
Answer:
sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x
Step-by-step explanation:
Given the expression: sin 2x + cos x,
then we can use the formula: sin 2x = 2 sin x cos x, which gives:
sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x
So there you have two expressions in terms of sin x and cos x, as requested. :D
The general form of slope-intercept form is y=mx+b
m stands for the slope
b stands for the y intercept
They are giving you m so you can replace m with -4/5 ⇒ y=-4/5x+b
Now you just need to find b. They also give you the point (0,-3). This means that when x is 0, y is equal to -3.
Lets go back to y=-4/5x+b and replace x with 0 and y with -3.
⇒ -3=(-4/5)(0) + b
⇒ -3= 0+b
⇒ -3=b
⇒ b=-3
Now that you have m and b, you can find your final answer in the form y=mx+b
⇒ y=-4/5x + (-3)
⇒ y= -4/5x - 3
Answer:
i believe it's -6? option a.
Step-by-step explanation:
okay.
60 degrees + a right angle, 90 degrees = 150 degrees
a triangle is normally 180 degrees.
180-150=30
so we need to get 30 from that equation, x + 36
x + 36 = 30
you solve.
x = -6
if im wrong, feel free to correct me + sub to gauthmath sub reddit if ya can !
Answer:
<h2><em><u>100</u></em></h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u> </u></em><em><u>,</u></em>
Radius of the cylinder = 5 cm
Height of the cylinder = 5 cm
<em><u>Therefore</u></em><em><u>, </u></em>
Total surface area of the cylinder




<em><u>Hence</u></em><em><u>,</u></em>
<em><u>The</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>value</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>put</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>green</u></em><em><u> </u></em><em><u>box</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>100</u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>