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M = n/V
.5M = n/.100 L
n = .1 L * .5M
n= .05 mols of MgCl2
mass of MgCl2 = .05 mols of MgCl2 * 95.211 grams/ 1 mol of MgCl2
mass of MgCl2 = 4.76 grams
4.76 grams of MgCl2 is needed to make 100 ml of a solution that is .500M, in chloride ion. Bolded = confused
Answer:
1s2 2s2 2p6 3s2 3p6 3d6 4s2
Explanation:
Answer:
D. 1:1
Explanation:
For every 1 mole of chlorine (Cl₂), there is one mole of calcium chloride (CaCl₂).
So, the mole ratio of chlorine to calcium chloride is 1:1.
Hope this helps. :)