Question

A quarter of a mole of neon gas is in equilibrium at 330 K in a container that has a volume of 5.0L.

Answer 1

Solution :

Given : Volume = 5 L, temperature = 330 K

a).  Moles in one litre,

    $n_1 =\frac{n}{V}$

         $=\frac{1}{20}$

Number of atoms = $n_1 \times N$

                             = $3 \times 10^{22}$

b). The thermal energy of the gas is :

 $U=\frac{f}{2} nRT$

 U = 10.16 L-atm

c). Given temperature, T = 380 K

  Therefore, Δ S = $\frac{f}{2}nR \ln\left(\frac{T_2}{T_1}\right)$

                            = 0.004 L-atm/K

d). When the expansion is negligible, the pressure of the heated gas is

   $P_2=\frac{nRT_2}{V}$

       = 1.56 atm