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GrogVix [38]
3 years ago
7

The high temperatures for a week are shown. 15°, 34°, 17°, 15°, 16°, 8° Which measure of center, mean or median, would BEST repr

esent the data?
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Hey there!

The mean would probably best represent the data.

This is because the mean of data is the average, which would show what the average temperature throughout the week was.

Have a super awesome day! :)

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\tt {Solution}

\tt {2 \frac{3}{4} + 5\frac{3}{5}}

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\tt {\frac{55+112}{20} }

\tt { \frac{167}{20} }

\tt {8 \frac{7}{20}}

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3 years ago
Uestion
Phoenix [80]
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3 years ago
Describe how to solve -5x = 30
Ivan
-5x divided by -5x to cancel the out the x and then 30 divided by -5, hope this helped!
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6:45AM
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3 years ago
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In a church wing with 8 men and 10 women members find the probability that a 5 member committee chosen randomly will have.......
Sergeeva-Olga [200]

Answer:

a) Probability that a 5 member committee will have all men = 0.0065

b) probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

Step-by-step explanation:

Number of men = 8

Number of women = 10

Total number of members = 10 + 8 = 18

Probability = (Number of possible outcomes)/(Total number of outcomes)

Number of ways of selecting a 5 member committee from 18 people = ^{18}C_5 = \frac{18!}{(18-5)!5!} = \frac{18!}{13!5!} = 8568 ways

a) Probability that a 5 member committee will have all men

Number of ways of selecting 5 men from 8 men

= ^8C_5 = \frac{8!}{(8-5)!5!} = \frac{8!}{3!5!} = 56 ways

Probability that a 5 member committee will have all men = 56/8568

Probability that a 5 member committee will have all men = 0.0065

b)probability that a 5 member committee chosen randomly will have 3men and 2 women​

Number of ways of selecting 3 men from 8 men

=  ^8C_3 = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = 56 ways

Number of ways of selecting 2 women from 10 men

=  ^{10}C_2 = \frac{10!}{(10-2)!2!} = \frac{10!}{8!2!} = 45 ways

Number of ways of selecting 3 men and 2 women = 56*45

Number of ways of selecting 3 men and 2 women = 2520

Probability of selecting 3 men and 2 women = 2520/8568 = 0.294

probability that a 5 member committee chosen randomly will have 3 men and 2 women = 0.294

6 0
3 years ago
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