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3 years ago

5

PLEASE PLEASE HELP WILL GIVE GIVE BRAINLIEST PLS!!!!!!!!!! Create a factorable polynomial with a GCF of 3x. Rewrite that polynom

ial completely factored. (10 points)

1 answer:

Naily [24]3 years ago

6 0

Answer:

Step-by-step explanation:

you can think in a reverse way:

Take

$3x(x^2+2x+3y^2)= 3x^3+6x^2+9xy^2.$

So the answer is

$3x^3+6x^2+9xy^2 = 3x(x^2+2x+3y^2)$

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How do i solve things that dont make sense to me even though i do know but dont know

kirill [66]

Answer:

Just try to make it make sense to you.

Step-by-step explanation:

For instance, a + 1 = 5

a = 4

We know that we should switch the terms as when it comes to normal numbers ,10 + 1 = 11 , 10 = 11-1. Therefore, the only trick is not to memorise, but try to understand the logic behind it. Hope this helps in some way???

7 0

2 years ago

Write a number that has four digits with the same number in all places such as 4444 circle the digit with the greatest value und

joja [24]

For example you can take the number 7 7 7 7

(7)77{7}

The first seven is the greatest it's 7,000

The last seven is the least its 7

HOPE THIS HELPS!!!

4 0

4 years ago

Complete this section.

choli [55]

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3 0

3 years ago

Read 2 more answers

Finding equation that passes through<br> (-3, -7) and (0, 8)

anygoal [31]

Answer:

y = 5x + 8

Explanation:

The slope is 5, and the y intercept is 8 so following the format of the equation, the equation for this line is:

y = 5x + 8

4 0

3 years ago

Read 2 more answers

Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace

joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean $\mu$ and default $\sigma$ , then the mean take seriously given as the straight line with a z score given by the confidence interval

$\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\$

Using formula:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

$P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)$

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

$=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z$

the required probability: $P(z>0.8349)=1-P(z$

4 0

3 years ago