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3 years ago

10

Dalia used a balancing move to begin to solve the

1 answer:

In-s [12.5K]3 years ago

8 0

To combine like terms and single out one term to take it easier to solve, the 6x was moved to the other side to combine like terms.
Subtracting 6x from 10x which is 4x

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Please help !!!!!!!! Now asap !!!!!

Andrej [43]

Answer: 4.026 x 10^0, 4.026

Step-by-step explanation:

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11 months ago

PLEASE ANSWER THE RIGHT ANSWER PLEASE DO NOT GUESS. PS, ITS MORE THAN ONE ANSWER. :)

Andreas93 [3]

Answer:

c

Step-by-step explanation:

idk lol so I am just putting random thing for this but that's the awnser

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3 years ago

Read 2 more answers

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

Why does 30+(-8)+(-6) equal 16? I'm so confused on this one

Daniel [21]

30+(-8)+(-6)
30-8-6
22-6
16

5 0

2 years ago

Read 2 more answers

"The product of four and a<br> number is more than ten."<br> ( write as an inequality thx)

lubasha [3.4K]

Answer:

4x > 10

Step-by-step explanation:

4x > 10

6 0

2 years ago